(u^4-3u^2+4)/(3(u^1/3))

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Solution for (u^4-3u^2+4)/(3(u^1/3)) equation: 


D( u )

3*((u^1)/3) = 0

3*((u^1)/3) = 0

3*((u^1)/3) = 0

3*(u/3) = 0

u = 0

u in (-oo:0) U (0:+oo)

(u^4-(3*u^2)+4)/(3*((u^1)/3)) = 0

(u^4-3*u^2+4)/(3*(u/3)) = 0

(u^4-3*u^2+4)/u = 0

(u^4-(3*u^2)+4)/(3*((u^1)/3)) = 0 // * 3*((u^1)/3)

u^4-(3*u^2)+4 = 0

u^4-3*u^2+4 = 0

t_1 = u^2

1*t_1^2-3*t_1^1+4 = 0

t_1^2-3*t_1+4 = 0

DELTA = (-3)^2-(1*4*4)

DELTA = -7

DELTA < 0

u belongs to the empty set

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